WebExpress the HCF of 468 and 222 as 468x + 222y where x and y are integers. Report ; Posted by Sarita Panda 1 year, 6 months ago. CBSE > Class 10 > Mathematics 1 answers; Preeti Dabral ... So HCF of 468 and 222 is (468 x -9 + 222 x 19) in the form 468x + 222y. 1 Thank You. ANSWER. WebExpress the HCF of 468 and 222 as 468x + 222y where x, y are integers in two different ways. Open in App. Solution. We need to express the H.C.F. of 468 and 222 as . Where x, y are integers in two different ways. Given integers are 468 and 222, where . By applying Euclid’s division lemma, we get .

Express hcf of 468 ,222 as 468x+222y where x,y are …

WebJun 2, 2024 · HCF of 468 and 222 468 = (222 x 2) + 24....(1) 222 = (24 x 9) + 6....(2) 24 = (6 x 4) + 0 Therefore, HCF = 6 6 = 222 - (24 x 9).....from(1) = 222 - (468 – 222 x 2) x … WebOct 9, 2024 · Find an answer to your question Express the HCF of 468 and 222 as 468x + 222y where X and Y are integers into different ways. honeynial6 honeynial6 09.10.2024 … cool back in the day

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WebExpress the HCF of 468 and 222 as 468x + 222y where x, y are integers in two different ways. 22. Find the smallest number which when increased by 17 is exactly divisible by both 468 and 520. 23. Show that one and only one out of n, (n + 2) and (n + 4) is divisible by 3, where n is any positive integer. 24. Web22. Express the HCF of 468 and 222 as 468x + 222y where x, y are integers in two different ways. Solution: Given that, we need to express the HCF of 468 and 222 as 468x + 222y, where x and y are integers in two different ways. So, here, the integers are: 468 and 222, and 468 > 222. Then, by applying Euclid’s division lemma, we get WebAnswer (1 of 2): 468 = 2 x 2 x 3 x 3 x 13 222 = 2 x 3 x 37 HCF = 2 x 3 = 6 6 = 222 - 216 = 222 - (24) 9 = 222 - (468–444)9 = 222 - (468)9 + (444)9 = 222 - (468)9 ... cool backlit keyboard