WebFPM formula Sheet 2 - Read online for free. pure math WebIf 2 sin 2 θ - cos 2 θ = 2 , then find the value of θ . Solution It is given that, 2 sin 2 θ - cos 2 θ = 2 ⇒ 2 sin 2 θ - 2 = cos 2 θ ⇒ - 2 1 - sin 2 θ = cos 2 θ ⇒ - 2 cos 2 θ = cos 2 θ 1 - sin 2 θ = cos 2 θ ⇒ 3 cos 2 θ = 0 ⇒ cos θ = 0 ⇒ θ = 90 ° Suggest Corrections 13 Similar questions Q. Question 12 If 2 sin2 θ−cos2 θ=2, then find the value of θ.
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WebOriginally Answered: If cos a / cos b = m and cos a / sin b = n, how do I show that (m^2 + n^2) cos^2 B = n^2 (here a=alpha, b=bita, ^ means power)? L.H.S. = (m² + n²) cos²b = (cos²a/cos²b + cos²a/sin²b) cos²b = cos²a (1/cos²b + 1/sin²b) cos²b = cos²a [ (sin²b+cos²b)/cos²b . sin²b ] cos²b = cos²a [ 1/cos²b . sin²b] cos²b = cos²a/sin²b = n² = R.H.S. WebOriginally Answered: If cos a / cos b = m and cos a / sin b = n, how do I show that (m^2 + n^2) cos^2 B = n^2 (here a=alpha, b=bita, ^ means power)? L.H.S. = (m² + n²) cos²b = … play doh sets cookie monster
7.1 Solving Trigonometric Equations with Identities
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